How do you write a polynomial in standard form given zeros 3, -4, 2?

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Answer 1 · 2016-03-25T08:21:20

#x^3-x^2-14x+24=0#

The method that I am used to is by equating each zero to the variable x

that is

#x=3# and #x=-4# and #x=2#

transposing the numbers to the left side, we have

#x-3=0# and #x+4=0# and #x-2=0#

so that we have the factors

#(x-3)*(x+4)*(x-2)=0#

multiply them to obtain the standard form

#(x^2+x-12)(x-2)=0#
#(x^3+x^2-12x-2x^2-2x+24)=0#
simplify to obtain the final answer

#x^3-x^2-14x+24=0#

God bless.... I hope the explanation is useful.