How do you write a polynomial in standard form given zeros 5, -1, -3i, 3i? Precalculus Polynomial Functions of Higher Degree Zeros 1 Answer A. S. Adikesavan May 1, 2016 x^4-4x^3+4x^2+36x-45=0. Explanation: The biquadratic equation is prod(x-zero)=(x-5)(x+1)(x-3i)(x+3i)=0 So, (x^2-4x-5)(x^2+9)=0, Expanding, . x^4-4x^3+4x^2+36x-45=0. Answer link Related questions What is a zero of a function? How do I find the real zeros of a function? How do I find the real zeros of a function on a calculator? What do the zeros of a function represent? What are the zeros of f(x) = 5x^7 − x + 216? What are the zeros of f(x)= −4x^5 + 3? How many times does f(x)= 6x^11 - 3x^5 + 2 intersect the x-axis? What are the real zeros of f(x) = 3x^6 + 1? How do you find the roots for 4x^4-26x^3+50x^2-52x+84=0? What are the intercepts for the graphs of the equation y=(x^2-49)/(7x^4)? See all questions in Zeros Impact of this question 2282 views around the world You can reuse this answer Creative Commons License