How do you write a polynomial with roots 3, –3, and 3 ?

1 Answer

Answer:

#x^3-3x^2-9x+27=0#

Explanation:

From the given: The roots are

#x=3# and #x=-3# and #x=3#

#x-3=0# and #x+3=0# and #x-3=0#

Multiply them all and equate to zero

#(x-3)(x+3)(x-3)=0#

#(x-3)(x^2-9)=0#

#(x^3-9x-3x^2+27)=0#

rearanging

#x^3-3x^2-9x+27=0#

God bless....I hope the explanation is useful.