How do you write a rule for the nth term given 28, 128, 228, 328, ...?

1 Answer
May 6, 2016

Answer:

#n^(th)# term of the series is #100n-72#

Explanation:

The series #28, 128, 228, 328, ...# is arithmetic series whose first term #a# is #28# and difference between a term and its preceding term #d# is #100#.

#n^(th)# term of an arithmetic series whose first term is #a# and common difference is #d# is #a+(n-1)d#.

Hence for above series it is #28+(n-1)100=28+100n-100=100n-72#