How do you write a second-degree polynomial, with zeros of -2 and 3, and goes to #-oo# as #x->-oo#?
1 Answer
Aug 3, 2017
Explanation:
#"since the zeros(roots) are "x=-2" and "x=3#
#"then the factors are"#
#x+2)(x-3)#
#rArry=(x+2)(x-3)#
#rArry=x^2-x-6#
#"for the condition that "yto-oo" as "xto-oo#
#"we require the coefficient of "x^2" to be negative"#
#rArry=-(x^2-x-6)#
#color(white)(rArry)=-x^2+x+6" is the required polynomial"#
graph{-x^2+x+6 [-20, 20, -10, 10]}