How do you write a slope-intercept equation for a line perpendicular to 3x + y - 2 = 0 with point (2,1)?
First put the equation in slope intercept form => slope = - 3
Product of slopes of perpendicular lines = - 1
So the perpendicular line has m = 1/3
Then use the point - slope formula and solve for just ' y '
to get the slope intercept form.