How do you write a slope-intercept equation for a line perpendicular to 3x + y - 2 = 0 with point (2,1)?

Aug 14, 2017

$y - 1 = \left(\frac{1}{3}\right) \left(x - 2\right)$
$y = \left(\frac{1}{3}\right) x + \frac{1}{3}$

Explanation:

First put the equation in slope intercept form => slope = - 3
Product of slopes of perpendicular lines = - 1
So the perpendicular line has m = 1/3
Then use the point - slope formula and solve for just ' y '
to get the slope intercept form.