Question

How do you write a slope-intercept equation for a line perpendicular to 3x + y - 2 = 0 with point (2,1)?

Answer 1

`y - 1 = (1/3) ( x - 2 )`
`y = (1/3) x + 1/3`

Explanation:

First put the equation in slope intercept form => slope = - 3
Product of slopes of perpendicular lines = - 1
So the perpendicular line has m = 1/3
Then use the point - slope formula and solve for just ' y '
to get the slope intercept form.