How do you write an equation for a circle with center (2,-6); tangent to the y-axis?

1 Answer
Nov 26, 2017

Answer:

The equation is: #(x-2)^2+(y+6)^2=4#

Explanation:

The equation of a circle with center #(h,k)# and radius #r# is:

#(x-h)^2 + (y-k)^2 = r^2#

We know the center is #(2,-6)#.

Since the circle is tangent to the y-axis, we know that the distance from the center to the y-axis is 2 units, so the radius is 2.

The equation is: #(x-2)^2+(y+6)^2=4#

Here's a figure:
graph{(x-2)^2+(y+6)^2=4 [-9.13, 10.87, -9.36, 0.64]}