How do you write an equation for a circle with center at (7, 3) and a diameter of 24?

1 Answer
Jul 20, 2016

Answer:

#(x-7)^2+(y-3)^2=144#

Explanation:

The standard form of the equation of a circle is.

#color(red)(|bar(ul(color(white)(a/a)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(a/a)|)))#
where (a ,b) are the coordinates of the centre and r, the radius.

Here centre = (7 ,3) hence a = 7 , b = 3 and r = 12

Substitute these values into the standard equation.

#(x-7)^2+(y-3)^2=12^2#

#rArr(x-7)^2+(y-3)^2=144" is the equation of the circle"#