# How do you write an equation for a circle with center C(3,-2) and radius 4?

Jul 4, 2016

${\left(x - 3\right)}^{2} + {\left(y + 2\right)}^{2} = 16$

#### Explanation:

The equation of a circle is

${\left(x - h\right)}^{2} + {\left(y - k\right)}^{2} = {r}^{2}$

Where $\left(h , k\right)$ are the center of the circle and $r$ is the radius

The center is $\left(3 , - 2\right)$ and $r = 4$

${\left(x - 3\right)}^{2} + {\left(y - \left(- 2\right)\right)}^{2} = {4}^{2}$

${\left(x - 3\right)}^{2} + {\left(y + 2\right)}^{2} = 16$