# How do you write an equation for a circle with center of (4,0) and has a radius of 2?

Apr 10, 2016

${\left(x - 4\right)}^{2} + {y}^{2} = 4$

#### Explanation:

The standard form of the equation of a circle is

$\textcolor{red}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} \textcolor{b l a c k}{{\left(x - a\right)}^{2} + {\left(y - b\right)}^{2} = {r}^{2}} \textcolor{w h i t e}{\frac{a}{a}} |}}}$

where (a , b) are the coords of centre and r , the radius

here (a , b) = (4 , 0) and r = 2 , and substituting these values into the equation.

rArr (x - 4)^2 + (y - 0)^2 = 2^2 → (x-4)^2 + y^2 = 4