# How do you write an equation for a circle with radius of 2 with it's centre being (-6,-8)?

Jun 9, 2016

${\left(x + 6\right)}^{2} + {\left(y + 8\right)}^{2} = 4$

#### Explanation:

The standard form of the equation of a circle is.

$\textcolor{red}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} \textcolor{b l a c k}{{\left(x - a\right)}^{2} + {\left(y - b\right)}^{2} = {r}^{2}} \textcolor{w h i t e}{\frac{a}{a}} |}}}$
where (a ,b) are the coordinates of the centre and r, is the radius.

here a = -6 , b = -8 and r = 2

$\Rightarrow {\left(x + 6\right)}^{2} + {\left(y + 8\right)}^{2} = 4 \text{ is the equation of the circle}$