How do you write an equation for the line that passes through (6,5) and (4,1)?

1 Answer
May 9, 2016

'The general equation of a line is y=mx+b where m is the slope and b is the intersection where x=0.

Explanation:

So you need to calculate m and b, the formula of the slope is m=(y_2-y_1)/(x_2-x_1)=(5-1)/(6-4)=4/2=2.
This formula tells us that for each step you give in x you climb m=2 in y. And now you can solve the equation and obtain b, so you take any point the line passes through, (6,5) for example.
5=2*6+b
and then
b=5-12=-7
And finally you have the line equation
y=(2)x+(-7)
graph{2x-7 [-16.75, 23.25, -8.24, 11.76]}