How do you write an equation in point slope and slope intercept form given point (3,2) and has a slope of -2?

1 Answer

Point Slope Form: #y-2=-2(x-3)#
Slope Intercept Form: #y=-2x+8#

Explanation:

The point-slope form formula is

#y-y_1 = "slope" * (x-x_1)#.

Here #x_1# #(3)# and #y_1# #(2)# are the coordinate points from your ordered pair #(3, 2)#.

Plug in those values, along with the slope, and you have an equation in point-slope form. Looking at this equation, you are able to distribute the #-2# (slope) to the values inside the parenthesis, and you can also isolate the #y# by adding the #2# from the "y" side to the other side.

You'll end up with

#y=-2x+8#

which is written in slope intercept form

#y=mx+b#

Here #m# stands for slope and #b# stands for the #y#-intercept.