How do you write an equation in standard form for a line through (1,2) with slope 4/5?

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Answer 1 · 2015-05-19T18:29:35

The formula for a line expressed in slope intercept form is:

#y = mx+c#

where #m# is the slope and #c# is the intercept.

We have been given #m = 4/5# and an example point with #x=1# and #y=2# which will satisfy this equation. Subtracting #mx# from both sides we have:

#c = y-mx = 2-(4/5xx1) = 2 - 4/5 = 10/5 - 4/5 = 6/5#

So the answer is:

#y = 4/5x+6/5#