# How do you write an equation in standard form for a line which passes through points (-10,-6) and (10,-8)?

May 16, 2015

x+10y= -70

First we get the slope $\frac{- 8 + 6}{10 + 10} = - \frac{2}{20} = - \frac{1}{10}$

Now point-slope form of the line would be y+6=$- \frac{1}{10}$(x+10)

This can now be simplified and put in to standard form.
10y+60= -x-10

x+10y = -70