Question

How do you write an equation in standard form for a line which passes through the point (5,2) and has a slope of -7/8?

Answer 1

Start with standard slope-point form:
`(y-y_1) = m(x-x_1)`
or for the given example with point `(x_1,y_1)(5,2)` and slope `m=-7/8`

`(y-2) = -7/8(x-5)`

`8(y-2) = -7(x-5)`

Converting to standard form: `Ax+By=C`

`7x +8y = 51`