# How do you write an equation in standard form for the line parallel to x-2y+7=0 and contains the point (-4,0)?

May 8, 2015

Standard form of: $y 1 = \frac{x}{2} + \frac{7}{2}$

Standard form of y2 that is perpendicular to y1:

y2 = -2x + b. (product of 2 slopes should be -1)#.

Find b by writing y2 passes at point (-4, 0).

0 = -2(-4) +b -> b = -8. Answer:

y = -2x - 8.