Question

How do you write an equation in standard form given a line that passes through (5,4), with m=-2/3?

Answer 1

point-slope form: `y-y_1=m(x-x_1)` where m=slope and `(x_1,y_1)` is the point

y-4= (-2/3)(x-5)
3y-12= -2x+10
`=>` 2x+3y-22=0