Question

How do you write an equation in standard form with integer coefficients for the line with slope 16/11 going through the point (-6,-1)?

Answer 1

Let's try using the relationship:
`y-y_0=m(x-x_0)`
Where:
`m` is the slope and `x_0,y_0` are the coordinates of your point:
`y-(-1)=16/11(x-(-6))`
`y+1=16/11x+96/11` common denominator `11`
`11y+11=16x+96`
`16x-11y=-85`