# How do you write an equation in standard form with integer coefficients for the line with slope 16/11 going through the point (-6,-1)?

$y - {y}_{0} = m \left(x - {x}_{0}\right)$
$m$ is the slope and ${x}_{0} , {y}_{0}$ are the coordinates of your point:
$y - \left(- 1\right) = \frac{16}{11} \left(x - \left(- 6\right)\right)$
$y + 1 = \frac{16}{11} x + \frac{96}{11}$ common denominator $11$
$11 y + 11 = 16 x + 96$
$16 x - 11 y = - 85$