How do you write an equation of a circle with center (6,-9) and diameter = 2sqrt7?
# ( x - 6 )^2 + (y+9)^2 = 7#
The standard form of the equation of a circle is :
# (x - a )^2 + (y - b )^2 = r^2#
where ( a , b ) is the centre and r , the radius.
The data required to complete the equation is given in this
question , centre (6 , - 9 ) and r =
# sqrt7 #
hence equation is :
#( x - 6 )^2 + (y + 9 )^2 = (sqrt7)^2#