How do you write an equation of a line given point #(3,-3) and m=1/3#?
1 Answer
May 15, 2017
Explanation:
#"the equation of a line in "color(blue)"point-slope form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))#
where m represents the slope and# (x_1,y_1)" a point on the line"#
#"here " m=1/3" and " (x_1,y_1)=(3,-3)#
#y-(-3)=1/3(x-3)#
#rArry+3=1/3(x-3)larrcolor(red)" in point-slope form"#
#"distributing and simplifying gives"#
#y+3=1/3x-1#
#rArry=1/3x-4larrcolor(red)" in slope-intercept form"#
