How do you write an equation of a line going through (-2,1) parallel to y = 1/2x - 3?

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Answer 1 · 2016-09-25T17:06:50

#y = 1/2x+2#

If the lines are parallel, then the slopes are the same.

#y = color(red)(1/2)x -3# gives you #color(red)(m=1/2)#

You also have a point, #(-2,1) " which is " (x,y)#

So, you can now substitute #m,x, and y " into " y=mx+c#
to be able to find #c#

#1 = (1/2) (-2) +c#

#1 = -1 + c#

#color(blue)(2 = c)#

#y = color(red)(1/2)x color(blue)(+2)#