Question

How do you write an equation of a line going through `2^x-5<64`?

Answer 1

As expressed this question does not make any sense.

Explanation:

`2^x-5 < 64` is not a point.

It could be solved for `x` as
`color(white)("XXX")2^x-5 < 64`

`color(white)("XXX")rarr 2^x < 69`

`color(white)("XXX")rarr log_2 2^x < log_2 69`

`color(white)("XXX")rarr x < log_2 69`

then using a calculator evaluating `log_2 69 ~~6.108524457`

In the Cartesian plane this is a region composed of all points to the left of `x = 6.108524457` (approx.)

I suppose you could argue that the equation `x=0` (for example) is the equation of a line going through (i.e. completely contained in) this region.