How do you write an equation of a line passing through (-16, -11), perpendicular to #y = -4x -2#?

1 Answer
Apr 22, 2018

Answer:

#y=1/4x-7#

Explanation:

#"the equation of a line in "color(blue)"slope-intercept form"# is.

#•color(white)(x)y=mx+b#

#"where m is the slope and b the y-intercept"#

#y=-4x-2" is in this form"#

#"with "m=-4#

#"given a line with slope m then the slope of a line"#
#"perpendicular to it is"#

#•color(white)(x)m_(color(red)"perpendicular")=-1/m#

#rArrm_("perpendicular")=-1/(-4)=1/4#

#rArry=1/4x+blarrcolor(blue)"is the partial equation"#

#"to find b substitute "(-16,-11)" into the partial equation"#

#-11=-4+brArrb=-11+4=-7#

#rArry=1/4x-7larrcolor(red)"perpendicular equation"#