# How do you write an equation of a line passing through (2, -8), perpendicular to #4x+5y=7#?

##### 1 Answer

#### Explanation:

First, you would want to get only

Then divide by 5:

Product of slopes of two perpendicular lines is

Now, make your new equation in point-slope format:

Now, to figure out the

Multiply

Adding

Make -8 and 5/2 have a common denominator:

Then you can put that into the point-slope formula and you're done!

graph{(y-5/4x+21/2)(5y-7+4x)=0 [-8.62, 11.38, -8.44, 1.56]}