How do you write an equation of a line passing through (4, -5), perpendicular to 2x-5y= -10?

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Answer 1 · 2018-04-08T10:41:02

#color(green)("Equation of the perpendicular line is "#

#color(crimson)(5x + 2y = 10#

#2x - 5y = 10#

#-5y = -2x + 10#

#y = (2/5)x - 2#

Slope of line #m_1 = (2/5)#

Slope of line 2 perpendicular to line 1 #m_2 = -1 / m_1 = -(1/(2/5)) = -5/2#

#"Equation of line 2 is given by " (y-y_2) = m * (x - x_2)#

#(y - (-5)) = -(5/2) * (x - 4)#

#2y + 10 = - 5x + 20#

#5x + 2y = 10#