How do you write an equation of a line perpendicular to y=3+2x, passing through (4, -1)?

May 9, 2017

$x + 2 y = 2$

Explanation:

Given line is y = 2x + 3. Its slope = 2

Let m be the slope of required line .
Then $m \times 2 = - 1$. So, m = - 1/2

Let the required equation be $y = - \frac{1}{2} x + c$

Since it passes through (4,-1), we get
$- 1 = - \frac{1}{2} \times 4 + c \mathmr{and} c = 1$

Hence the equation is $y = - \frac{1}{2} x + 1$

$\Rightarrow x + 2 y = 2$