How do you write an equation of a line that has a intercept of 2 and passes through (12, 4)?

1 Answer
Oct 25, 2016

color(green)(x-6y=-12)

Explanation:

If the line has a y-intercept of 2 then it passes through (x_1,y_1)=(0,2)
and since we are told that it also passes through (x_2,y_2)=(12,4)
we can write the line's equation in two-point form as:
color(white)("XXX")(y-2)/(x-0)=(4-2)/(12-0)

Simplifying:
color(white)("XXX")y-2=x(1/6)

color(white)("XXX")6y-12=x

or in standard form:
color(white)("XXX")x-6y=-12
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