How do you write an equation of a line through (-2,5) and parallel to 2y=4x-6?

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Answer 1 · 2016-11-17T03:08:19

Please see the explanation.

Write the equation of the new line as:

#y = 2x + b#

Substitute -2 for x and 5 for y:

#(5) = 2(-2) + b#

Solve for b:

#b = 9#

The equation of the line that is parallel to #2y = 4x - 6# and goes through the point #(-2,5)# is:

#y = 2x + 9#