How do you write an equation of a line through the the point (-5, -3) and is parallel to the line 7x+2y=5?
2 Answers
2y+
Explanation:
Since they're parallel, this means that they have the same gradient. So start by finding the gradient of the line by using the line equation provided,
To do this, it as to be in the
So:
2y= 5-
y=
The gradient is the co-efficient of
So:
m= -
Next step is finding the y-intercept (c). To do this we make use of the gradient and the point provided.
So you get:
-3 = (-
Here, notice that I'm using
Now, let's find c:
-3 =
c= -
Now, SUBSTITUTION TIME!
y= -
Take 2 to the other side by multiplication:
2y=
Then:
2y+
Explanation:
∙ Parallel lines have equal slopes
the equation of a line in slope-intercept form is.
∙xy=mx+b
where m is the slope and b the y-intercept
rearrange 7x+2y=5 into this form
subtract 7x from both sides and divide by 2
2y=−7x+5
y=−72x+52←in slope-intercept form
with slope m =−72
y=−72x+b←is the partial equation
to find b substitute (−5,−3) into the partial equation
−3=352+b⇒b=−62−352=−412
y=−72x−412←in slope-intercept form
multiply through by 2
2y=−7x−41
7x+2y=−41←in standard form