How do you write an equation of a line with (4,0) and slope 1/3?

1 Answer
Apr 7, 2015

There are several ways to write an equation of the line with (4,0) and slope #1/3#.

  1. Use Point-Slope form
  2. Use Slope-Intercept form

First, Point-Slope form : #y - y_1=m(x-x_1)# where m is your slope, and the ordered pair you are given is #(x_1,y_1)#.
So write: #y - 0 = 1/3(x-4)#.
Simplify if you wish: #y = 1/3x-4/3#.

Or, Slope-Intercept form : y = mx + b, where m is your slope, and b is the y-intercept (not given).
So, write: #y = 1/3x+b #
Then, use your ordered pair to substitute in for x and y, and solve for b: #0 = (1/3)(4)+b#
#0 = 4/3+b# (subtract #4/3# from both sides)
#(-4)/3=b# and replace into the original form: #y = 1/3x-4/3#