# How do you write an equation of a line with point (3,-3) slope 3?

##### 3 Answers

#### Explanation:

We can simply apply the formula;

Where

Hence

Hence when rearanging to yields;

#### Explanation:

#"the equation of a line in "color(blue)"slope-intercept form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))#

#"where m is the slope and b the y-intercept"#

#"here "m=3#

#rArry=3x+blarrcolor(blue)"is the partial equation"#

#"to find b substitute "(3,-3)" into the partial equation"#

#-3=9+brArrb=-12#

#rArry=3x-12larrcolor(red)"in slope-intercept form"#

The answer is

#### Explanation:

I am assuming that you need this in slope-intercept form. You already know that the slope is

you can fill in

Now, all that you need to do is solve for

So first you change

Another way to do this is by plugging in

Now just plug in