Question

How do you write an equation of a line with Slope = -2, passing through (0, - 3)?

Answer 1

The quick answer is `y = -2x-3`

The equation of a line can be expressed as `y=mx+c`, where `m` is the slope and `c` is the intercept - that is the value of `y` where the line intercepts the `y` axis.

In your case, the intercept value `c=-3`, so if we were being particularly pernickity the slope intercept form of the equation would be:

`y = (-2)x + (-3)`

Another standard form for the equation of a line is called "point slope" form. In general it looks like this:

`y - y_0 = m(x - x_0)`

where `m` is the slope and `(x_0, y_0)` is some point the line goes through.

In your case, we could write:

`y - (-3) = (-2)(x - 0)`

or more simply:

`y + 3 = -2x`