# How do you write an equation of a line with Slope = 4, passing through (1, 3)?

May 19, 2015

You can write the linear equation in the point-slope form .

$y - {y}_{1} = m \left(x - {x}_{1}\right)$,

where $m$ is the slope, $4$, and the point $\left(1 , 3\right)$ is $\left({x}_{1} , {y}_{1}\right)$ .

Point-slope form: $y - 3 = 4 \left(x - 1\right)$

This equation can also be written in slope-intercept form by solving for $y$ . The general form is $y = m x + b$, where $m$ is the slope and $b$ is the y-intercept.

$y - 3 = 4 \left(x - 1\right)$

Distribute the $4$.

$y - 3 = 4 x - 4$

Add $3$ to both sides.

$y = 4 x - 4 + 3$ =

Slope-intercept form: $y = 4 x - 1$