Question

How do you write an equation of the horizontal line passing through the point (-7,4)?

Answer 1

`y=4`

Explanation:

`"A horizontal line is parallel to the x-axis and passes "`
`"through all points in the plane with the same y-coordinate"`

`"the equation is "y=c`

`"where c is the value of the y-coordinate the line passes"`
`"through"`

`"the point here is "(-7,4)`

`rArry=4" is the equation of the line"`
graph{(y-0.001x-4)((x+7)^2+(y+4)^2-0.04)=0 [-10, 10, -5, 5]}

Answer 2

`y = 4`

Explanation:

A horizontal line has a slope of `0` and thus pases through all points of `x in RR` Which includes `x=-7`

The equation of a straight line with slope `(m)` and `y-`intercept `(c)` is:

`y=mx+c`

In this case `m=0 and c = 4`

Hence, `y=4` is the equation of our straight line. as shown in the graphic below.

graph{(y-0.000x-4)((x+7)^2+(y-4)^2-0.1)=0 [-14.24, 14.24, -7.12, 7.12]}