# How do you write an equation of the line in standard form with m=-1/2, goes through (-3/4)?

Dec 6, 2015

$x + 2 y - 5 = 0$

#### Explanation:

When you know the slope $m$ and a point $\left({x}_{0} , {y}_{0}\right)$ of a line, the equation becomes

$y - {y}_{0} = m \left(x - {x}_{0}\right)$

In your case, -assuming that with "(-3/4)" you meant the point $\left(- 3 , 4\right)$- you have

$y - 4 = - \frac{1}{2} \left(x + 3\right)$

$y = - \frac{1}{2} x - \frac{3}{2} + 4$

$y = - \frac{1}{2} + \frac{5}{2}$

$2 y = - x + 5$

$x + 2 y - 5 = 0$