How do you write an equation of the line with slope 3/7 containing the point (3,8)?

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Answer 1 · 2015-11-08T01:39:34

#y = mx + b#

We already know the slope, what remains is to find the #y#-intercept. To find the #y#-intercept, simply plug-in any known value for #x# and #y#.

#=> y = 3/7x + b#
#=> 8 = 3/7(3) + b#
#=> 8 = 9/7 + b#
#=> 56 = 9 + 7b#
#=> 47 = 7b#
#=> 47/7 = b#

Hence, the equation of the line is

#y = 3/7x + 47/7#