How do you write an expression for the acid ionization constant (K_aKa) for HFHF?

1 Answer
Apr 23, 2018

Well we write the equation first off....

Explanation:

HF(aq) + H_2O(l) rightleftharpoonsH_3O^+ +F^(-)HF(aq)+H2O(l)H3O++F

...and this reaction is not so complete as the lower hydrogen halides in that H-FHF is certainly quite strong, and ALSO, the F^-F is disfavoured entropically in aqueous solution.

And so we write K_a=([H_3O^+][F^(-)])/([HF(aq)])=7.2xx10^-4Ka=[H3O+][F][HF(aq)]=7.2×104...