How do you write an inequality and solve given "the sum of nine times a number and fifteen is less than or equal to the sum of twenty four and ten times the number"?

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Answer 1 · 2016-10-02T22:46:30

The inequality for this is #9x+15<=24+10x#.

Now that we know what our inequality is, we can now solve for #x#. To do this, we have to subtract 24 from each side:

#9x+15-24<=24+10x-24#

#9x-9<=10x#

Next, let's subtract #9x# from each side:

#9x-9-9x<=10x-9x#

#-9<=9x#

Finally, let's divide each side by 9 to get our answer:

#-9/9<=(9x)/9#

#-1<=x#