# How do you write as a single log for #1/3log_3x + 2/3log_3x #?

##### 1 Answer

Oct 29, 2015

#### Explanation:

#1/3 log_3(x) + 2/3 log_3(x) = (1/3 + 2/3) log_3(x) = log_3(x)#

Oct 29, 2015

#1/3 log_3(x) + 2/3 log_3(x) = (1/3 + 2/3) log_3(x) = log_3(x)#

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