# How do you write as a single log for #log_460 - log_44 + log_4x #?

##### 1 Answer

Dec 11, 2015

I think you intended

If so, then using the basic properties of logs this simplifies to:

#log_4 15x#

#### Explanation:

In general,

and

So:

#log_4 60 - log_4 4 + log_4 x#

#=log_4 (60/4) + log_4 x#

#=log_4 15 + log_4 x#

#=log_4 15x#