How do you write as a single logarithm $1/2 Log _b3 +1/2 Log_bx - 3 Log_b Z$ ?

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Answer 1 · 2018-03-15T12:17:21

$log_b(sqrt(3x)/Z^3)$

Since $xlogy=logy^x$ , we can write:

$log_bsqrt(3)+log_bsqrt(x)-log_bZ^3$

Since $loga+logb=log(ab)$ , we write:

$log_bsqrt(3x)-log_bZ^3$

Since $loga-logb=log(a/b)$ , we can write:

$log_b(sqrt(3x)/Z^3)$

How do you write as a single logarithm 1/2 Log _b3 +1/2 Log_bx - 3 Log_b Z1/2 Log _b3 +1/2 Log_bx - 3 Log_b Z?