Question

How do you write as a single logarithm `Log_b 2 + Log_bx- Log_by`?

Answer 1

`log_b 2 + log_b x − log_b y = log_b ((2x)/y)`

Explanation:

`log_c a + log_c b = log_c (ab)`
`log_c a - log_c b = log_c (a/b)`