How do you write as a single logarithm $Log_b 5 +1/3 Log_bx$ ?

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Answer 1 · 2015-07-20T02:20:56

I found: $log_b(5x^(1/3))=log_b(5root3(x))$

You can use the fact that:
$alogx=logx^a$
and:
$loga+logb=log(axxb)$
So you get:
$log_b(5)+log_b(x^(1/3))=$
$=log_b(5x^(1/3))$

How do you write as a single logarithm Log_b 5 +1/3 Log_bxLog_b 5 +1/3 Log_bx?