Question

How do you write as a single logarithm `Log_b 5 +1/3 Log_bx`?

Answer 1

I found: `log_b(5x^(1/3))=log_b(5root3(x))`

Explanation:

You can use the fact that:
`alogx=logx^a`
and:
`loga+logb=log(axxb)`
So you get:
`log_b(5)+log_b(x^(1/3))=`
`=log_b(5x^(1/3))`