# How do you write b^-5*b^-9 using only positive exponents?

${b}^{-} 14 = \frac{1}{b} ^ 14$

#### Explanation:

We can combine the terms:

${b}^{-} 5 \times {b}^{-} 9$

${b}^{- 5 - 9}$

${b}^{-} 14$

And then using the identity ${x}^{-} 1 = \frac{1}{x}$, we can rewrite as:

${b}^{-} 14 = \frac{1}{b} ^ 14$