How do you write equations of a line parallel to x - y - 12 = 0xy12=0 that passes through (2, -5)?

1 Answer
Apr 9, 2015

Re-write the equation x-y-12=0xy12=0 into a slope-intercept form y=mx+by=mx+b

y = (1)x-12y=(1)x12

So we are looking for line with slope of 11 through the point (2,-5)(2,5)

This can easily be achieved using the slope-point form of the equation: (y-y_1) = m(x-x_1)(yy1)=m(xx1)

In this case y_1= (-5)y1=(5), x_1=2x1=2, and m=1m=1

So our equation is
y+5 = (1)(x-2)y+5=(1)(x2)
which simplifies as
y= x-7y=x7