How do you write #g(x) = -2|x+1|# as a piecewise function?
1 Answer
Mar 13, 2016
#g(x) = { (-2(x+1), x >= -1), (2(x+1), x < -1) :}#
Explanation:
#abs(t) = { (t, t >= 0), (-t, t < 0) :}#
Hence:
#abs(x+1) = { ((x+1), x >= -1), (-(x+1), x < -1) :}#
Multiply by
#g(x) = { (-2(x+1), x >= -1), (2(x+1), x < -1) :}#
