# How do you write log_243 3 =1/5 in exponential form?

I found: $3 = {243}^{\frac{1}{5}}$
You can use the definition of log where the base of the log $243$ becomes the base of the exponential with $\frac{1}{5}$ as exponent; you get:
${\log}_{243} 3 = \frac{1}{5}$
$3 = {243}^{\frac{1}{5}}$
or: $3 = {243}^{\frac{1}{5}} = \sqrt[5]{243}$