How do you write #nsqrt3sqrt2# as a fractional exponent?

1 Answer
Mar 4, 2018

#(6n)/sqrt6#

Explanation:

Note that #sqrt(3)sqrt(2)=sqrt(2xx3)#

If you are not sure about this consider:
#sqrt(4)sqrt(4) = 4= sqrt(4xx4)#

So we have: #nsqrt(3)sqrt(2)=nsqrt(6)#

Multiply by 1 and you do not change the value. However, 1 comes in many forms.

#color(green)(nsqrt(6)color(red)(xx1) color(white)("dddd")=color(white)("dddd") nsqrt(6)color(red)(xxsqrt6/sqrt6)#

#color(green)(color(white)("dddddddddd")->color(white)("dddd") (6n)/sqrt6)#