How do you write the augmented matrix for the system of linear equations $7x+4y=22, 5x-9y=15$ ?

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Answer 1 · 2017-08-01T16:59:22

The solution is $((x),(y))=((258/83),(5/83))$

The equations are

$7x+4y=22$

$5x-9y=15$

The augmented matrix is

$((7,4,|,22),(5,-9,|,15))$

$R2larr7R2-5R1$

$((7,4,|,22),(0,-83,|,-5))$

$R2larr(R2)/(-83)$

$((7,4,|,22),(0,1,|,5/83))$

$R1larrR1-4R2$

$((7,0,|,1806/83),(0,1,|,5/83))$

$R1larr(R1)/7$

$((1,0,|,258/83),(0,1,|,5/83))$

How do you write the augmented matrix for the system of linear equations 7x+4y=22, 5x-9y=157x+4y=22, 5x-9y=15?